(x^2-49)(2x^2-17x+8)=0

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Solution for (x^2-49)(2x^2-17x+8)=0 equation: 


Simplifying
(x2 + -49)(2x2 + -17x + 8) = 0

Reorder the terms:
(-49 + x2)(2x2 + -17x + 8) = 0

Reorder the terms:
(-49 + x2)(8 + -17x + 2x2) = 0

Multiply (-49 + x2) * (8 + -17x + 2x2)
(-49(8 + -17x + 2x2) + x2(8 + -17x + 2x2)) = 0
((8 * -49 + -17x * -49 + 2x2 * -49) + x2(8 + -17x + 2x2)) = 0
((-392 + 833x + -98x2) + x2(8 + -17x + 2x2)) = 0
(-392 + 833x + -98x2 + (8 * x2 + -17x * x2 + 2x2 * x2)) = 0
(-392 + 833x + -98x2 + (8x2 + -17x3 + 2x4)) = 0

Combine like terms: -98x2 + 8x2 = -90x2
(-392 + 833x + -90x2 + -17x3 + 2x4) = 0

Solving
-392 + 833x + -90x2 + -17x3 + 2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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